8x^2+72x-4756=0

Solution for 8x^2+72x-4756=0 equation:

8x^2+72x-4756=0

a = 8; b = 72; c = -4756;
Δ = b2-4ac
Δ = 722-4·8·(-4756)
Δ = 157376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{157376}=\sqrt{64*2459}=\sqrt{64}*\sqrt{2459}=8\sqrt{2459}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-8\sqrt{2459}}{2*8}=\frac{-72-8\sqrt{2459}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+8\sqrt{2459}}{2*8}=\frac{-72+8\sqrt{2459}}{16}
$